3. Consider the hypothesis testgiven by

H_0: u = 670

H_1: u does not equal 670

In a random sampleof 70 subjects, the sample meanis found to be 678.2. The population standard deviationis known to be omega = 27.

(a) Determine the P-value for this test. (Show work)

(b) Is there sufficient evidence to justify the rejection of H_0 at the omega = 0.02 level? Explain.

4. The playing times of songs are normally distributed. Listed below are the playing times (in seconds) of 10 songs from a random sample. Use a 0.05 significance level to test the claim that the songs are from a population with a standard deviation less than 1 minute.

448 231 246 246 227 213 239 258 255 257

(a) What are your null hypothesis and alternative hypothesis?

(b) What is the test statistic? (Show work)

(c) What is your conclusion? Why? (Show work)

5. Given a sample size of 25, with sample mean 736.2 and sample standard deviation 82.3, we perform the following hypothesis test

H_0: u = 750

H_1: u < 750

What is the conclusion of the test at the omega = 0.10 level? Explain your answer. (Show work)

3. Consider the hypothesis test given by

H_0: u = 670

H_1: u does not equal 670

In a random sample of 70 subjects, the sample mean is found to be 678.2. The population standard deviation is known to be omega = 27.

(a) Determine the P-value for this test. (Show work)

Test value t=(678.2-670)/(27/sqrt(70))=2.54

P value=TINV(2.54,69,2)=0.0133 (TINV is a function in EXCEL, 69 is the degree of freedom, 2 means two tailed t test).

(b) Is there sufficient evidence to justify the rejection of H_0 at the omega = 0.02 level? Explain.

Since P value …

The expert rejects the null hypothesis in statistics.