If you have a normal distributionof a random variablex, with a meanof 56 and standard deviationof 8: What is the probabilitythat the random variable x will be within plus or minus 1 standard deviation of the mean?
What is the probability that x is greater than 64?
What is the probability that x is less than 42?
Refer to this weeks case study. With the 24 means that we accumulated in our survey, we can get a pretty good picture of what kind of money we might be making after a few years. After all, we are certain that the distribution of the sample results (i.e., money spent in the bakery. was normal, which means that the distribution of those means we calculated is also normal. Because we have a samplingdistribution, we have a much better idea of the true mean of our income than if we just took the mean of one sample and used it to approximate our income. Find the probability of my income being between $90 and $92 per visit.
Refer to this weeks case study. For the following take the values of the means I got, set them up as a probability distribution (which is normal), and then find the population mean and standard deviation. The mean (µ) turns out to be $85 per visit and the standard deviation (s) $16 per visit. Find the probability of my income being greater than $80 per visit.
Refer to this week’s case study. Find the probability of my income being less than $89 per visit.