A paired difference experiment produced the following results
a) Determine the values of z for which the null hypothesis, m1 -m2 = 0, would be rejected in favor of the alternative hypothesis, m1 – m2 < 0. Use a = 0.10
b) Conduct the paired difference test described in part a. Draw the appropriate conclusions.
c) What assumptions are necessary so that the paired difference test will be valid.
d) Find a 90% confidence intervalfor the meandifference.
Here it is given that,
= 38, = 92, = 95.5, = -3.5, = 21
Since the sample size >30, the test statistic for testing the null hypothesis is given by,
follows a Standard Normal distribution.
a) The test statistic is given by,
= – 4.7081
b) Since the alternative hypothesis is a lower tailed test, the critical region of the test is given by,
, where is the critical value.
Here =0.10. So the critical value of the test is given by,
= – 1.28
Since z = – 4.7081 < – 1.28 = , we …
The solution contains a Paired Difference Test and the determination of the confidence interval for the mean difference.