It is known that the IQ scores of workers in a certain company are normally distributed with a standard deviationof ten. If 0.13% of the workers have IQ’s in excess of 130 calculate the meanIQ.
Probability corresponding to x > 130 is 0.13% 0r 0.0013
Prob(z)=1-Prob(x > 130)= …
Probability values have been calculated using Normal Distribution