Two hundred candidates took each of two examination papers. The diagram shows the cumulative frequency graphs for their marks.
i) Estimate the medianmarks for each of the papers.
ii) State, with a reason, which of the two papers was the easier one.
iii) It is suggested that the marks on Paper 2 were less varies than those on Paper 1. Use interquartile ranges to comment on this suggestion.
An additional two questions are attached.
See the attached file.
Median = (N+1)/2 th term i.e. 100.5 th term
So we take the average of marks obtained by 100th and 101st student
Median (Paper 1) = 38 (approx. from graph)
Median (Paper 2) = 61 (approx. from graph)
(ii) In the easier paper, more students will score higher marks. Hence, the median for the easier paper should be higher. Since, …
This post show how to calculate median, interquartile range and other descriptive statistics using the cumulative frequency chart.