A component is comprised of two halves. The thickness of each half is normally distributed with a meanof 2 millimeters and a standard deviationof 0.1 millimeter and the halves are independent.
a. Determine the mean and standard deviation of total thickness of the two halves. Answer E(T)=4 , and sigma of T=0.1414 ?
b. What is the probabilitythat the total thickness exceeds 4.3 millimeters?
Mean = 2ml + 2 ml = 4ml
Variance = sum of variances
variance of total = …
This solution shows step-by-step calculations to determine the mean and standard deviation and also the probability of the total thickness exceeding 4.3 millimeters.