The average length of stay in a chronic disease hospital for a certain type of patient is 60 days with a standard deviationof 15. Suppose it is reasonable to assume an approximately normal distributionof legths of stay.
a) What percentage of patients stay less than 50 days?
Fill in the blanks ….
(Please see the attachmen)
Mean = 60, SD = 15
(a) X = 50, then z = (X ?Mean)/SD = (50 ?60)/15 = -10/15 = -0.67.
Probability that a person stays less than 50 …
The percentage of patients stay less than 50 days is found. A Complete, Neat and Step-by-step Solution is provided.