The Statistical Abstract of the United States published by the US Census Bureau reports that the average annual consumption of fresh fruit per person is 99.9 pounds. The standard deviate of fresh fruit consumption is about 30 pounds. Suppose a researcher took a random sampleof 38 people and had them keep a record of the fresh fruit they ate for one year.

a. What is the probabilitythat the sample average would be less than 90 pounds?

b. What is the probability that the sample average would be between 98 and 105 pounds?

c. What is the probability that the sample average would be less than 112 pounds?

d. What is the probability the sample average would be between 93 and 96?

The solution file is attached.

= 99.9, = 30, n = 38

of the sample = 30/38 = 4.87

z = (x – )/

(a) z = (90 – 99.9)/4.87 = -2.03

P(x < 90) = Area under …

The expert examines the normal distribution for a fresh fruit consumption. The probability that the sample average would be between 98 and 105 pounds is determined. Neat and Step-by-step solutions to all the questions.