Electric circuit analysisproblems. See attached file for full problem description.
Please refer to attachment.
R=1 ohm I(mA)
V L= 400 mH I
For the inductive circuit we can write the following equation using Kirchhoff’s loop law :
V = RI + L dI/dt ………(1)
From the given graph I vs t we can write the following equation for the current as a function of time :
I = ¼ t ……….(2)
Substituting For I from (2) in (1) :
V = R(1/4 t) + L d/dt(1/4 t)
Or V = (R/4) t + L/4
Substituting R = 1 ohm, L = 400 mH = 0.4 H
V = ¼ t + 0.1 ………(3)
Voltage described by (3) will generate the current shown in the above graph. It is shown in …
Two problems on electric circuit analysis. Problem 1 dealing with current and voltage in an inductive circuit has been solved using Kirchhoff’s loop law. Problem 2 deals with magnitude of current for opening of a fuse in an inductive circuit.