I am working through this problem and part A is easy enough to show but part b and c have me wondering if I am on the right path.
For part b–
I get the point p = r’ sin(theta) – r
Then dV = k*sigma * 2 * pi * r’ ^2 cos(theta) d(theta)/ (r’^2 + r^2 – 2 r r’ sin(theta))^(1/2)
For integration, apply substitution method:
(r’^2 + r^2 – 2 r r’ sin(theta)) = x
=> -2 r r’ cos(theta) d(theta) = dx
When theta = -pi/2, …
Electric potential due to charged spherical shell is estimated.